Question

so I need help with the steps to simplify this: csc(arctan x)
I know that sqrt(x^2 +1) = sec t
and x = tan t; t= arctan(x)

Answer 1

sorry for the lousy picture, but cosecant is "hypotenuse over opposite" at least that is the simpleminded way of thinking about it

Answer 2

you get
\[\frac{\sqrt{1-x^2}}{x}\] in one step after solving for the hypotenuse

Answer 3

ah, it was the picture I was having trouble with. Thanks!