Question

(3-2i)(4-2i)

Answer 1

any ideas? there are two ways to do this. one is just to multiply out and when you get
\[i^2\] replace it by -1

Answer 2

the other is to know that
\[(a+bi)(c+di)=(ac-bc)+(ad+bc)i\] and go directly to the answer

Answer 3

Would it be 12-14i+4(-1) ?

Answer 4

8-14i ?

Answer 5

Yes

Answer 6

(3-2i)(4-2i) = 12 - 14i +4i^2
= 8 - 14i

Answer 7

yes! which way did you use?

Answer 8

8-14 i thanks for your help!!