Why is gravitational potential negative?
Because it is always calculated from a height above the ground level. And, acceleration due to gravity(g) is taken negative in upward direction. So, according to formula, U = Mgh, where "g" is negative
Why is it calculated above the ground level?
Because potential energy means the energy possessed by a body at a height from the ground level. So, height is a must condition for calculating Potential energy.
Where is the ground level?
If it's on the Earth, shouldn't the acceleration be taken as positive?
i think it isn't negetive allways it's sign depped on your frame direction
choose of ground level is arbitrary you can take that every where
gravitation is calculated in negative direction as it is acting downwards and perpendicular to a body
yes it's normal to mass but you can get downward positive
Aadarsh is not wrong, the reason why gravitational potential is negative is purely mathematical. Now, see according to newton, every mass particle creates a field around it, where it affects another mass particle if it is placed in it(i.e. exerts a force). The gravitational potential at a point around a mass is the work done to bring a unit mass substance from a random far enough point(infinity) to that point. This is potential at point x: \[Potential(x)=W(\infty)-W(x)\] Take \[x=\infty\] \[Potential(\infty)=W(\infty)-W(\infty)=0\] Thus potential at infinity is zero. Thus \[Potential(x)=0-W(x)\] =-W(x) Thus gravitational potential is always negative.
when we say gravitational potential energy is negative in the physical sense it means that a body having negative gravitational potential energy is BOUND to the earth we all have negative gravitational potential energy(it means we are attracted to the earth's surface and bound to it) whenever we calculate escape velocity, we equate the final energy at infinity to be equal to 0 as all the negative part of gravitational potential energy has been made positive and that the body acquiring escape velocity is no longer BOUND to the earth and has 0 energy with respect to this regard
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