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find the range of values of k if the equation (2-3k)x2 + (4-k)x+2=0 has two different roots
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(2-3k)x^2 + (4-k)x+2=0 delta = (4-k)^2 - 8(2-3k) > 0 = k^2 - 8k + 16 - 16 + 24k >0 = k^2 + 16k >0 = k ( k + 16) >0 Thus k < 0 or k > 16
Given k ( k + 16) >0, what about the case where k< 0 AND (k + 16) <0?
k<-16 or k>0
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