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find the range r if the quadratic equation x(x-2)=2(x+r) has no real roots
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HINT: Discriminant will be less than 0
x^2 -2x - 2x -2r = 0 x^2 - 4x - 2r = 0 delta = 4 + 2r < 0 -> r < -2
x^2 -2x - 2x -2r = 0 x^2 - 4x - 2r = 0 (-4)^2 -4(1) (-2r)<0 16 +8r<0 8r<-16 r<-2.... is it right?
yes, seems good to my tired eyes.
haha..Thank You
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