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AB and CD are two equal chords of a circle with centre O.OP and OQ are perpendiculars on chords AB and cd respectively.if
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105 degrees POQ forms an isosceles triangle with one angle of 150 deg, therefore the other two must be 15. the angle APQ is this angle plus the right angle between the chord and the perpendicular, so 90 +15 = 105 degrees
no d correct answer is <APQ=75
ok i think i just had a and b the other way round
K
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