Question

We have measured that a person who jumps up vertically from the ground up can reach a height of h = 70 cm.
(a) Determine the starting velocity va which the person has at the moment he let the earth

Answer 1

use the equations for constant acceleration:
u = ?, s = 0.70 m, g = -9.8 cm/s^-2, v = 0
v^2 = u^2 - 2gs
0 = u^2 - 2 * 9.8 * 0.7
u^2 = 19.6 * 0.7 = 13.72
u = sqrt 13.72 = 3.7 m/s

Answer 2

what is u?

Answer 3

initial velocity