Find the perimeter of this triangle
Below are each sides
5a^2+12a-8
14a^2-8a-9
a-5

Question

Find the perimeter of this triangle
Below are each sides
5a^2+12a-8
14a^2-8a-9
a-5

rogue · Answer

Just add up the lengths of each side to find the perimeter.$$(5a^2+12a-8) + (14a^2-8a-9) + (a-5) = 5a^2 + 14a^2 + 12a - 8a + a - 8 - 9 - 5$$$$5a^2 + 14a^2 + 12a - 8a + a - 8 - 9 - 5 = 19a^2 + 5a - 22$$

anonymous · Answer

P = ( 5a^2+12a-8) + (14a^2-8a-9) +(a -5)  = 19a^2 + 5a -22

anonymous · Answer

I noticed some signs were changed?

My answer is 1/38....That can't be right?? Can it?

phi · Answer

both answers above are the same (and correct).  How did you get a number.  Do you  have a value for a?

anonymous · Answer

I solved 19a^2+5a-22

phi · Answer

tol solve it, you need an equation.  For example
19a^2+5a-22=0
(which can't be the case here, if it really is the perimeter, it is not zero.)

unless you have left out some info, the problem just give us expressions that we add up.