Question

How is it that (2^n)/(2^n-1) simplifies to : (1)/(1-(1/2)^n)

Answer 1

easier to work backwards probably to see it

Answer 2

\[\frac{1}{1-\frac{1}{2^n}}\]
\[\frac{1}{\frac{2^n-1}{2^n}}\]
\[\frac{2^n}{2^n-1}\]

Answer 3

divide top and bottom by 2^n

Answer 4

thank you I got it now.