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Given x/x^2-9 - x/x^2+6x+9, perform the indicated operation and simplify the result.
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\[\frac{x}{(x-3)(x+3)}-\frac{x}{(x+3)^2}\] \[\frac{x(x+3)-x(x-3)}{(x+3)^2(x-3)}\] \[\frac{x^2+3x-x^2+3x}{(x+3)^2(x-3)}=\frac{6x}{(x+3)^2(x-3)}\]
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