Question

Last question! When you factor completely, the factors of 16-x^4 are: ?

Answer 1

difference of 2 squares: (4-x^2)(4+x^2)
(2-x)(2+x)(4+x^2)

Answer 2

do you want imaginary number factors as well?

Answer 3

if you include imaginary numbers, fully factored would be:
(2-x)(2+x)(x-2i)(x+2i)

Answer 4

(4-x^2)(4+x^2) are the solutions so,
4-x^2=0
4=x^2
+ 2 or -2=x

4+x^2=0
x^2=-4
x= square root -4
or 2i

Answer 5

You guys are awesome. Thanks!