how many square meters of canvas is required for a conical tent whose height is 3.5 m and radius of whose base is 12m?(pie=22/7)
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OpenStudy (anonymous):
in detail i want d answer
OpenStudy (anonymous):
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OpenStudy (anonymous):
area of canvas required = Curved Surface Area of the cone
CSA of cone = π*r*l so we first need to find l
l = sqroot(r^2 + h^2) = sqroot[(12m)^2 + (3.5m)^2] = sqroot[ 144 m^2 + 12.25 m^2]
OpenStudy (mihai):
471 square meters
OpenStudy (anonymous):
l = 12.5 m
so
CSA = 22/7 * 12m * 12.5 m = 471.43 sqmtr
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OpenStudy (anonymous):
thxs to alllllllllllllllll
OpenStudy (anonymous):
answer is 471.4
OpenStudy (anonymous):
Hmm don't we consider the base?
OpenStudy (anonymous):
@vengeance921
we r not given that the base is also canvas. for the language above we just need to find the CSA
OpenStudy (anonymous):
True, thanks.
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OpenStudy (anonymous):
Thanks, except for adding the base your calc was also right