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sec =6. where feta lies in quadrant 4. What is tan?
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Tan is negative. And whats feta? lol
1 + tan squared theta = sec squared theta tan squared theta = 36 - 1 tan theta = - √ 35
4th quadrant cos is positive so 1/cos or sec is positive so cos = 1/6 draw a triangle and find the missing side using pythagoras |dw:1329734922801:dw| 6^2 - 1^1 = x^2 \[x = -\sqrt{?}\] so \[\tan (\theta) = 1/\sqrt{35}\]
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