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sec theta = square root of 2. Where theta lies in Quadrant 1. What is tan theta.
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|dw:1329735386616:dw| so\[1/\cos = \sqrt{2} \] \[\cos = 1/\sqrt{2}\] use pythagoras... but missing side is 1 unit tan = 1
oops 1 should be on the x axis,.... and you need to find the opposite side
1 + tan theta squared = sec theta squared tan theta squared = 2 - 1 tan theta = 1 (positive in Quad I)
why is the missing side one unit?
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