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solve (x-1) ----- -1/4(x-2)=1 3
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Is this your question \[\frac{x-1}{3}-\frac{1}{4(x-2)}=1\]
\[(x-1)/3-1(x-2)/4=1\] \[4(x-1)-3(x-2)/12=1\] \[4x-4-3x+6=12\] \[x+2=12\] \[x=12-2=10\]
@Parvathy-Is (x-2) in denominator or numerator?
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