Question

find of f'(x) of f(x)= f(x) = (4 x^2 - 3)^3 (-9 x^2 - 6)^11

Answer 1

just use product, power and chain rules

Answer 2

I did I wanna see how you are suppose to do it because apparently Im doing it wrong lol

Answer 3

\[3(4x^2-3)^2(8x)(-9x^2-6)^{11}+(4x^2-3)^311(-9x^2-6)^{10}(-18x)\]

Answer 4

yeah maybe its requiring me to foil it out.... cuz that is exactly what i got