Can someone tell me how to solve this please? http://desmond.imageshack.us/Himg33/scaled.php?server=33&filename=48085603.jpg&res=medium Options: a) 10^12 b) 10^14 c) 10^8 d) 10^10
Do those dots mean multiplication?
Yep, they do
I was just wondering if theres a way to solve that without going through the whole process
im sure there is.. hold on
I'm not used to that form. It's difficult for me to see what's going on there.
Bahrom, can you re-post that in a form I might be able to understand?
(103-3)^4=100^4
How do you know where the parentheses are?
ok let's see: 103^4 - 4 * 103^3 * 3 + 6 * 103^2 * 3^2 - 4 * 103 * 3^3 + 3^4
there are no parethesis, Hero.
parentheses*
103^4 - 103^3 * 2^2 * 3 + 103^2 * 2 * 3^3 - 2^2 * 103 * 3^3 + 3^4
hold on let me write this out on paper.. i got lost in powers lol
Interesting cinar. I'm used to x's and y's being there to use binomial theorem.
that is (x+y)^4, where x = 100, y = 3
we can show that by grouping.. (i think) trying to get into the form (100+3)^2 (100+3)^2 gimme a sec.
mehh.. grouped wrong.. these 103s are annoying.. hold on, this is one of those problems that's going to nag me until i get it right haha will get there eventually..
This is the binomial expansion of \((103 - 3)^4 = 100^4 = 100,000,000\) The way I saw this quickly is by noticing that the first coefficient of each term is 1, 4, 6, 4, 1 from first to last. Those correspond to 4-choose-0, 4-choose-1, 4-choose-2, 4-choose-3, and 4-choose-4 respectively. Also, the very first term was \(103^4\) which means that 103 is the first term in the binomial you want to expand. Likewise, \(3^4\) was the last, so 3 was the other term. Finally, I knew that it was \((103-3)^4\) instead of \((103+3)^4\) because there were alternating plus and minus signs. Does this make sense?
If you want it as one of the options, notice that \(100^4 = (10^2)^4=10^8\)
Oh, thank you so much! I appreciate your answers.
You're very welcome.
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