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Mathematics 48 Online
OpenStudy (anonymous):

Can someone tell me how to solve this please? http://desmond.imageshack.us/Himg33/scaled.php?server=33&filename=48085603.jpg&res=medium Options: a) 10^12 b) 10^14 c) 10^8 d) 10^10

hero (hero):

Do those dots mean multiplication?

OpenStudy (anonymous):

Yep, they do

OpenStudy (anonymous):

I was just wondering if theres a way to solve that without going through the whole process

OpenStudy (bahrom7893):

im sure there is.. hold on

hero (hero):

I'm not used to that form. It's difficult for me to see what's going on there.

hero (hero):

Bahrom, can you re-post that in a form I might be able to understand?

OpenStudy (anonymous):

(103-3)^4=100^4

hero (hero):

How do you know where the parentheses are?

OpenStudy (bahrom7893):

ok let's see: 103^4 - 4 * 103^3 * 3 + 6 * 103^2 * 3^2 - 4 * 103 * 3^3 + 3^4

OpenStudy (anonymous):

there are no parethesis, Hero.

OpenStudy (anonymous):

parentheses*

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Binomial_theorem

OpenStudy (bahrom7893):

103^4 - 103^3 * 2^2 * 3 + 103^2 * 2 * 3^3 - 2^2 * 103 * 3^3 + 3^4

OpenStudy (bahrom7893):

hold on let me write this out on paper.. i got lost in powers lol

hero (hero):

Interesting cinar. I'm used to x's and y's being there to use binomial theorem.

OpenStudy (bahrom7893):

that is (x+y)^4, where x = 100, y = 3

OpenStudy (bahrom7893):

we can show that by grouping.. (i think) trying to get into the form (100+3)^2 (100+3)^2 gimme a sec.

OpenStudy (bahrom7893):

mehh.. grouped wrong.. these 103s are annoying.. hold on, this is one of those problems that's going to nag me until i get it right haha will get there eventually..

OpenStudy (kinggeorge):

This is the binomial expansion of \((103 - 3)^4 = 100^4 = 100,000,000\) The way I saw this quickly is by noticing that the first coefficient of each term is 1, 4, 6, 4, 1 from first to last. Those correspond to 4-choose-0, 4-choose-1, 4-choose-2, 4-choose-3, and 4-choose-4 respectively. Also, the very first term was \(103^4\) which means that 103 is the first term in the binomial you want to expand. Likewise, \(3^4\) was the last, so 3 was the other term. Finally, I knew that it was \((103-3)^4\) instead of \((103+3)^4\) because there were alternating plus and minus signs. Does this make sense?

OpenStudy (kinggeorge):

If you want it as one of the options, notice that \(100^4 = (10^2)^4=10^8\)

OpenStudy (anonymous):

Oh, thank you so much! I appreciate your answers.

OpenStudy (kinggeorge):

You're very welcome.

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