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Find the value of x in the interval (-π, 0) where the graph of the function fx = x+2sinx has a horizontal tangent line.
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why is nobody viewing this aahhhhhhhh
\[f'(x)=2\cos x\]This is zero when cosx is zero. This occurs at x=-pi/2
I believe the derivative should be "f'(x) = 1 + 2cos x."
ooops....made an error. should be f'(x)=1+2cosx. This gives -1/2=cosx...
so \[x=\frac{-2\pi}{3}\]
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