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Picture help. Using kite LMON, solve for x A: 21 B: 7 C: 4 D: cannot be determined
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NO=MO so \[6x+17=9x-4\] Can you find x now?
How would I find it?
\[6x+17=9x-4\] add 4 to both sides \[6x+17=9x-4+4\] \[6x+21=9x\] subtract 6x from both sides \[21=3x\] divide both sides by 3 \[7=x\] hence \[x=7\]
OH! Can't believe I did not know that... :/
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no worries, try next time:)
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