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Mathematics 17 Online
OpenStudy (anonymous):

evaluate limx->0 ((sqrt3-x)-(sqrtx+3))/(x)

OpenStudy (anonymous):

Try rationalizing numerator.

OpenStudy (anonymous):

I tried not getting the right answer, can you plz show me?

OpenStudy (anonymous):

((sqrt3-x)-(sqrtx+3))/(x) * ((sqrt3-x)+(sqrtx+3))/((sqrt3-x)+(sqrtx+3)) 3 - x - x -3/2x(((sqrt3-x)+(sqrtx+3)))

OpenStudy (anonymous):

wait where'd you get the 2x from?

OpenStudy (anonymous):

rationalization...

OpenStudy (anonymous):

I don't understand, wouldn't it just be 3 - x - x -3/x(((sqrt3-x)+(sqrtx+3)))?

OpenStudy (anonymous):

|dw:1329762670499:dw|

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