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evaluate limx->0 ((sqrt3-x)-(sqrtx+3))/(x)
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i did it for you, what is confusing you?
multiply both top and bottom by (sqrt3-x)+(sqrt3+x)
I just need someone to show me how it would be 2x. wouldn't it just be evaluate just x instead of 2x?
ir wait.. just use Lhopitals rule
http://www.wolframalpha.com/input/?i=limx-%3E0+%28%28sqrt%283-x%29%29-%28sqrt%28x%2B3%29%29%29%2F%28x%29 click on show steps
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Is it possible to do it without applying that rule, since I never learned that rule.
hold on let me write this out..
okay :)
|dw:1329763505962:dw|
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