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Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. tan^2B = 4
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|dw:1329765647534:dw| is that your question?
Yes it is.
okay it can be rewritten as |dw:1329765756874:dw| does that help?
\[\tan B = \pm 2\] since B is between 0 and 90 just find arctan (2)
campbell is right I was just trying to lead you down that path instead of giving it to you
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One thing I feel nesscary to mention is this|dw:1329765918164:dw|
thats to the negative one it cut off my drawing for some reason
So when it says to find it to the nearest degree. You do the arctan of 2 which is 63.4349. So my anwser will be 63 degrees?
looks like it
Okay thanks!
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