Assume that 2 cars in 12 is defective and will not start. If at different times 5 individuals each randomly select a car to test drive, what is the probability that at least 1 of them selects a car that will not start?____________?

Question

rulnick · Answer

The prob of at least 1 getting a nonstarter is 1 minus the prob they all get good cars.  So ...

rulnick · Answer

The answer is 1 - (10/12)^5.

rulnick · Answer

Which is
1- (5/6)^5 = 1 - 3125/7776.

rulnick · Answer

Or 0.60 (rounded to nearest hundredth).

anonymous · Answer

that wasnt it

rulnick · Answer

They are selecting "at different times," right?  So it is possible for two people to select the same car, right?

rulnick · Answer

4651/7776 is another form of the answer.  Is that the one you are looking for?

anonymous · Answer

That was right