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Integrate [(e^(x) + e^(-x) )/(e^x - e^(-x)]
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\[\large \int\limits\frac{e^{x}+e^{-x}}{e^{x}-e^{-x}} dx\] let u = \(e^x+e^-x\) => \(\frac{du}{e^{x}+e^{-x}} \)
Can you work it out more?
\[\large \int\limits\frac{e^{x}+e^{-x}}{u} *\frac{du}{e^{x}+e^{-x}} => \int\limits\frac{1}{u} => \ln(u) + C =>\] \[\large \ln(e^x-e^-x) +c\]
woops, typo: \[\ln(e ^{x} -e ^{-x}) +c\]
Thank you ^^
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