Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

Answer 1

hello

Answer 2

the given line is :y=-3x+7 so its slope is -3
the slope of the perpendicular is 1/3
so its equation is y=(1/3)*x+n
now substitute (6;-1) in it:
-1=2+n=>n=-3
so:y=(1/3)*x-3