Question

find all the zeros & state the multiplicity
y= x^3+x^2-19x+5

Answer 1

\[(x+5) (x^2-4 x+1)\] so -5 with multiplity 1, then quadratic formual for other two

Answer 2

actually for
\[x^2-4x+1=0\] easier to complete the square
\[x^2-4x=-1\]
\[(x-2)^2=-1+4=3\]
\[x+2=\pm\sqrt{3}\]
\[x=-2\pm\sqrt{3}\]

Answer 3

typo\[x=2\pm\sqrt{3}\]

Answer 4

what do you mean typo? which part

Answer 5

dont you see my ''x''= 2+-sqrt3
but satellite73'1 is different than me..

Answer 6

he made typo..