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solve and find the complex roots of 125x^3 + 343 = 0
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sum of two cubes \[a^3+b^3=(a+b)(a^2-ab+b^2)\] in this case you have \[(5x)^3+7^3\]
factor as \[(5x+7)(25x^2-35x+49)\]
one root is \[-\frac{7}{5}\] other two complex roots via the quadratic formula
so I use the quad formula for the 25x^2 - 35x + 49 right?
Yes
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okay thanks
\[x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
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