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OpenStudy (anonymous):
rulnick one quick question about 300(A+12) = 1000A 3A+36=10A
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OpenStudy (anonymous):
how did you get the 3A?
OpenStudy (rulnick):
300(A+12) = 1000A distribute the 300 ... 300A + 3600 = 1000A divide both sides by 100 ... 3A+36=10A
OpenStudy (anonymous):
i see thanks
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