Question

http://www.twiddla.com/584234

Answer 1

twiddling 88% and not moving on...:(

Answer 2

\[\frac {\frac {6x + 9}{15x^2}}{\frac {16x - 12}{10x^4}} = \frac {6x + 9}{15x^2} \times \frac {10x^4}{16x - 12}\]

Answer 3

\[\frac {6x + 9}{15x^2} \times \frac {10x^4}{16x - 12} = \frac {3(2x + 3)}{15x^2} \times \frac {10x^4}{4(4x - 3)}\]

Answer 4

\[\frac {3(2x + 3)}{15x^2} \times \frac {10x^4}{4(4x - 3)} = \frac {3(2x + 3)}{4(4x - 3)} \times \frac {2x^2}{3}\]

Answer 5

\[ \frac {3(2x + 3)}{4(4x - 3)} \times \frac {2x^2}{3} = \frac {x^2(2x + 3)}{2(4x - 3)}\]

Answer 6

Thats all I guess.