In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.0800 s, during which time it experiences an acceleration of 229 m/s2. The ball is launched at an angle of 52.3 ° above the ground. Determine the (a) horizontal and (b) vertical components of the launch velocity.

Question

anonymous · Answer

launch velocity = a * t = 229 *0 .08 m/s
vertical component = (229*0.08) * sin 52.3
horizontal component =  (229*0.08) * cos 52.3

anonymous · Answer

need any more help?

anonymous · Answer

I have some other questions.  Feel like a moron, though.  It's been a while since I've looked at stuff like this.
:P

anonymous · Answer

unfortunately i need to go in 5 minutes
do you want me to work out the above computations?

anonymous · Answer

If you could.

anonymous · Answer

Much appreciated.

anonymous · Answer

launch velocity - 18.32 m/s
vertical component = 14.5 m/s
horizontal component = 11.2 m/s