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Mathematics 21 Online
OpenStudy (anonymous):

Factor 15x^2-26x+8

OpenStudy (rulnick):

(5x-2)(3x-4)

OpenStudy (anonymous):

How?

OpenStudy (rulnick):

Can check by FOIL. To factor requires a bit of trial and error, "reverse FOIL."

OpenStudy (freckles):

15(8)=5(24)=10(12)=20(6) -26=-26-6 -26x=-26x-6x \[15x^2-26x-6x+8\] Factor by grouping we shall

OpenStudy (freckles):

oops type0

OpenStudy (freckles):

i'm so bad

OpenStudy (freckles):

\[-26=-20-6\]

OpenStudy (freckles):

\[-26x-20x-6x\]

OpenStudy (freckles):

so we have \[15x^2-20x-6x+8\]

OpenStudy (anonymous):

Thank you both.

OpenStudy (freckles):

\[5x(3x-4)-2(3x-4)=(3x-4)(5x-2) \]

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