Question

Compute this Bernoulli Trial:
At least 4 failures in 7 trials with p = 0.75______?

Answer 1

Is p the probability of failure?

Answer 2

success

Answer 3

4 failures:
prob of failure is .25
prob of success is .75

C(7, 4) .25 ^ 4 times .75 ^ 3 =

Answer 4

5 failures

C(7,5) .25^5 * .75 ^2 =

Answer 5

6 failures:

C (7,6) .25 ^6 * .75 ^1 =

Answer 6

7 failures

C(7,7) .25^7 * .75 ^0 = .25^7 =

Answer 7

@CW ---> Time for you to multiply and add

Answer 8

sorry man i have been back and forth t

Answer 9

We have to do some arithmetic.

Answer 10

C(7, 4) .25 ^ 4 times .75 ^ 3 + C(7,5) .25^5 * .75 ^2 + C (7,6) .25 ^6 * .75 ^1 + C(7,7) .25^7 * .75 ^0 =

Answer 11

I have my instructor on email now

Answer 12

Thats why I am back and forth

Answer 13

Did you get .070556 approx?

Answer 14

Deal with your instructor first. Then, we'll finish this.

Answer 15

He helped me answer a couple were done I am trying to do some supposed to be easier stuff with random variables and density functions

Answer 16

I will post a couple more of these

Answer 17

I have two more that i am stuck on