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Solve |x + 8| ≤ 5. x ≤ –13 or x ≥ –3??
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\[|f(x)| \le 5\] => \[-5 < f(x)<5 \]
^ luis is correct :)
\[-5 \le f(x) \le 5 = > -5 \le x+8 \le 5 => -13 \le x \le -3\]
|x + 8| ≤ 5 -5 ≤x + 8 ≤ 5 -5 -8 ≤ x ≤ 5 -8 => -13 ≤ x ≤ -3
@ChinaGurl ---> This is an AND problem and not an OR problem. x ≥ -13 AND x≤ - 3 which can be written as above: -13 ≤ x ≤ -3
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