Identify the precipitate (if any) that forms when KOH and Cu(NO3)2 are mixed
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OpenStudy (anonymous):
What are the products of the reaction? (Hint: its a double displacement)
OpenStudy (anonymous):
I have no idea. this information was not given
OpenStudy (anonymous):
When you mix KOH and Cu(NO3)2
KOH + Cu(NO3)2 -> Cu(OH)2 + KNO3
Using my solubility chart, I see that all solutions of consisting of NO3- ions are soluable
and that since Cu2+ isnt in the special cases of OH- to be soluable together,
Cu(OH)2 is the precipitate that forms
OpenStudy (anonymous):
Thanks. Could You tell me the phases each element
OpenStudy (anonymous):
Well what state is a precipitate in?
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OpenStudy (anonymous):
Aq
OpenStudy (anonymous):
No, a precipitate is something that is not soluable in your solution, which is a solid.
The solutions on the other hand are (aq)
OpenStudy (anonymous):
Get it?
OpenStudy (anonymous):
so in this case the precipitate would be Cu(OH)2
OpenStudy (anonymous):
Yeah...
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