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Chemistry 11 Online
OpenStudy (anonymous):

Identify the precipitate (if any) that forms when KOH and Cu(NO3)2 are mixed

OpenStudy (anonymous):

What are the products of the reaction? (Hint: its a double displacement)

OpenStudy (anonymous):

I have no idea. this information was not given

OpenStudy (anonymous):

When you mix KOH and Cu(NO3)2 KOH + Cu(NO3)2 -> Cu(OH)2 + KNO3 Using my solubility chart, I see that all solutions of consisting of NO3- ions are soluable and that since Cu2+ isnt in the special cases of OH- to be soluable together, Cu(OH)2 is the precipitate that forms

OpenStudy (anonymous):

Thanks. Could You tell me the phases each element

OpenStudy (anonymous):

Well what state is a precipitate in?

OpenStudy (anonymous):

Aq

OpenStudy (anonymous):

No, a precipitate is something that is not soluable in your solution, which is a solid. The solutions on the other hand are (aq)

OpenStudy (anonymous):

Get it?

OpenStudy (anonymous):

so in this case the precipitate would be Cu(OH)2

OpenStudy (anonymous):

Yeah...

OpenStudy (anonymous):

ok. Thanks

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