Question

I dont get what to do
For each function, (a) find f(0), (b) solve f(x).
Heres the problems
1.f(x)=x^2-13x+40
2.f(x)=3-1/2x
3.f(x)=2-3x

Answer 1

For the f(0), just replace x with 0. For instance:
1. f(0) = 0^2 -13(0) + 40 = 40.

Answer 2

2. f(0)=3
3. f(0)=2

Answer 3

For (b), there's missing info. Do you mean "solve f(x)=0"?

Answer 4

yah sorry...

Answer 5

For (2) is it 3-(1/2)x or 3-1/(2x)?

Answer 6

IDK

Answer 7

For (3) it is 0=2-3x, so x=2/3.

Answer 8

For (1) it is 0 = x^2-13x+40, so x = 5 or x = 8 (two solutions).

Answer 9

Thank you