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OpenStudy (anonymous):
How do you factor (4k^2+4k-15)?
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OpenStudy (anonymous):
ac grouping ac=-60 4k^2-6k+10k-15 2k(2k-3)+5(2k-3) (2k+5)(2k-3)
OpenStudy (anonymous):
Oh, OK. Thank you.
OpenStudy (anonymous):
|dw:1329847781530:dw|
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