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Mathematics 18 Online
OpenStudy (anonymous):

How do you factor (4k^2+4k-15)?

OpenStudy (anonymous):

ac grouping ac=-60 4k^2-6k+10k-15 2k(2k-3)+5(2k-3) (2k+5)(2k-3)

OpenStudy (anonymous):

Oh, OK. Thank you.

OpenStudy (anonymous):

|dw:1329847781530:dw|

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