The line y = 2x + 3 is tangent to the parabola y = x2 + B. Find B. Can someone explain this step by step
so y=x^2+B => y'=2x+0 =>y'=2x The slope of the tangent line is 2 so 2x=2 => x=1 =>y=2(1)+3=5 =>5=1^2+B =>5-1=B =>B=4
ahhh makes sense now
awesome! :)
I just dont get why you plug that x back into the tangent line equation then set the it equal to the b equation
I'm trying to the connect the relationship but idk
ok well i know that (x,y) is on both y=x^2+B and y=2x+3
well the point that they touch I'm calling (x,y)
we knew x
from setting the derivative=slope of the tangent line and solving for x
so i had enough info to find out what y was on y=2x+3
which would also be the same y on y=x^2+B
AH thats right the derivative of that equation is the slope at that point?
Yep! :)
SWEET thank you! I wish I could give you two medals for this lol!
i give medal too -- theres your second medal! :D
I don't need medals. I just need your love (platonic love of course). :)
Thanks you guys. You are so sweet.
You has my math thats more than my love.
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