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The sum of a number its square is 30. Find the number.
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let the number be x\[x+x^2=30\]\[x^2+x-30=0\]\[(x+6)(x-5)=0\]\[x=-6 ,5\]
so x + x^2 = 30 then the have the quadratic x^2 +x - 30 = 0 (x - 5)(x+6)=0 then x = 5 or -6
-6 and 5 both work
why... (-6)^2 = 36 36 + (-6) = 30.... condition met
exactly^^
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