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Chemistry 15 Online
OpenStudy (anonymous):

Determine the percent composition of Na2CO3

OpenStudy (anonymous):

I think the percent composition of Na2CO3 is around 105.99 %

OpenStudy (anonymous):

Na = 23g x (2) = 46g C = 12g x (1) = 12g O = 16g x (3) = 48g Total = 106g I'm guessing that's the percentage. lol

OpenStudy (anonymous):

That is what I thought! I hope that was what the teacher was looking for

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