27 - x^3
27 - x^3 3^3 - x^3 = (3 - x) ( 9 + 3x + x^2)
Selma, if you have any question, feel free to ask. Thanks for your medals :)
Thank you so much, this is really helpful because I have a test tomorrow and I need to know how to do these problems. I will for sure. :)
The formula is a^3 - b^3 = (a -b) ( a^2 + ab + b^2)
Thanks, I have the formulas written down on a paper. :)
Watch out if a^3 + b^3, = (a +b) ( a^2 - ab + b^2)
Thank you. :)
I like the way that you follow up with your posts, proving that you want to learn!
Your math surely will be improved dramatically in no time :)
Yeah, I always go through the problem step by step to know how they got the answer. I need to pass this class and I really like math. I don't know why I don't get how to do these sometimes. They seem so simple but yet again, I feel dumb not knowing how to figure them out.
No, you're not dumb AT ALL!
It's just your teacher doesn't know how to explain!
There're so many excellent solvers in this site! Make sure you show up on weekend, and prepare to ask as many as possible!
Do you have any question more?
I will forsure and you're right, my teacher is too fast and i go at a slow pace. but yeah i do have another question. x^3 - x= -2x^2 + 2
x^3 + 2x^2 - x - 2 = 0 x ( x^2 - 1) + 2 ( x^2 -1) = 0 (x^2 -1)( x + 2) = 0 => x = 1, x = -2
would this be right then for this problem 2(x-4)(x-5)= 0 it would be x-4 = 0 or x-5= 0 then x=4, x=5?
2(x-4)(x-5)= 0 In order for the whole product = 0 either each of group = 0 x - 4 = 0 ---> x = 4 x- 5 = 0 ---> x = 5
Thank you so much :)
Don't be affraid to ask, the more questions, the more clearer for your mind!
Well, I would ask more, but It's almost 2 am and I have to get up at 7. So I'm going to go to bed.
I'm about to tell you that, because it's 3am my time, now!
Good night and Good luck with your exam!
Goodnight and thank you. :)
BTW, what grade are you?
College, freshman.
You definitely need to show up more and more on this web site :) See you around!
I will, see yaa. :)
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