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the area of a yard is 6x^2-5X+4.If length is (3x-2)feet what is its width
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assume that the yard is rectangular area = length x width width = are/length w = 6x^2-5x +4/3x-2 can you do that?
2x-1/3+(10/3)/(3x-2)?
how would you set this problem up?
the same way you would set up 223523/23 through long division
what do you mean set up? draw?
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yes how would you write this out
|dw:1329909395107:dw|
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