Question

get invers from f(x) = x^3 / x^2 + 1

Answer 1

We have
\[f(x)= \frac{x^3}{x^2}+1
\]
it can be written as
\[ f(x)=x+1\]
write x as \(f^{-1}(x)\)
we get
\[ f(f^{-1}(x))=f^{-1}(x)+1\]
we know that
\[f(f^{-1}(x))= x\]
so
\[x=f^{-1} (x)+1\]
or
\[f^{-1} (x)=x-1\]