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If f(x) = -1/2x -3 find f^1(x)
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f^1(x)=f(x), do you want an inverse instead?
Lib \[f^1(x)=f(x)= \frac{-1}{2x-3}\]
for this one i am going to guess that you have \[f(x)=-\frac{1}{2}x-3\]
which means the inverse we find by writing \[x=-\frac{1}{2}y-3\] and solve for y \[x+3=-\frac{1}{2}y\] \[-2x-6=y\] \[f^{-1}(x)=-2x-6\]
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