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What is the center and radius of the following circle: x2 + (y – 6)2 = 50 A. C (6, 0), r = 7. 07 B. C (0, -6), r = 7. 07 C. C (0, 6), r = 50 D. C (0, 6), r = 7. 07
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(x-h)^2+(y-k)^2=r^2 (h,k) is center r is radius (h,k)=(0,6) r=sqrt(50)
so is it C?
no, does sqrt(50)=50?
yea?
\[\sqrt{50}=50?\]
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D
oh never mind it doesnt
\[\sqrt{50} \approx 7.07\]
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