Question

Factor g2 – 64

a) (g – 1)(g + 64)
b) (g + 8)(g – 8)
c) (g – 8)(g – 8)
d) (g + 8)(g + 8)

Answer 1

b

Answer 2

b :) use DOTS (difference of two perfect squares)

Answer 3

g^(2)-64

The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
(g-8)(g+8)

Answer 4

its kinda making sence...i just get confused easily