In the figure, △ABC ~ △DEF, ∡ABG ≅∡GBC, and ∡DEH ≅∡HEF. Solve for x.

http://go.flvs.net/courses/1/flvs_57_3641_12419/ppg/respondus/pool_Geom_3641_0304_04/image0074e25b182.gif

Question

In the figure, △ABC ~ △DEF, ∡ABG ≅∡GBC, and ∡DEH ≅∡HEF. Solve for x.

http://go.flvs.net/courses/1/flvs_57_3641_12419/ppg/respondus/pool_Geom_3641_0304_04/image0074e25b182.gif

anonymous · Answer

The link you provided conflicts with ADblocker

anonymous · Answer

http://go.flvs.net/courses/1/flvs_57_3641_12493/ppg/respondus/pool_Geom_3641_0304_05/image0064e25b3e2.gif

istim · Answer

Cyter, just disable it.

istim · Answer

I should too.

anonymous · Answer

I am just lost with this lesson, any help would be appreciated. Also same to my other questions on my profile. 
:)

paxpolaris · Answer

there is no ∡ABG

anonymous · Answer

sorry ignore last link. http://go.flvs.net/courses/1/flvs_57_3641_12493/ppg/respondus/pool_Geom_3641_0304_04/image0074e25b182.gif

paxpolaris · Answer

If the big triangles are similar you can use the AA test to show$$\Large \triangle GBC \sim \triangle HEF$$

anonymous · Answer

I don't get this at all Pax, please explain

paxpolaris · Answer

Then, $$\Large{\cancel{16}8 \over \cancel{26}13}={ x+9 \over 2x+5}$$

paxpolaris · Answer

As they are similar triangles the proportion of the corresponding sided is the same
$$\Large{HE \over GB} = {EF \over BC}$$

anonymous · Answer

yes they are simiar but just different size

anonymous · Answer

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