Question

integral of:
tan^78 (x) * sec^4 (x)

Answer 1

sec^4 = sec^2 *sec^2

use trig substitution
sec^2 = 1+tan^2

--> tan^78 *(1+tan^2)*sec^2
u = tan x
du = sec^2 x

--> u^78(1+u^2) du