Question

Please, check if I'm correct.
5).Complete the square: 0 = - 5x^2 + 10x - 10
(A) (x - 1)^2 = -5
(B) (x - 1)^2 = 5
(C) (x - 1)^2 = - 1*******
7). If the discriminant is positive-- if b^2 -4ac > 0 --then the quadratic equation
(A) has two solutions********
(B) has one solution
(C) has no solutions

Answer 1

7.A

Answer 2

You're right!
5C and 7A :)
- 5x^2 + 10x = 10
-5 ( x^2 - 2x) =10
-5 [ (x -1)^2 - 1 ] = 10
(x -1)^2 - 1 = -2
(x -1)^2 = -1

Answer 3

That's the right answer. Thanks.