Polynomial Functions Evaluate
f(2t-1)= (2t-1)^2-2(2t-1)-1 Please Show Steps.

Question

Polynomial Functions Evaluate
f(2t-1)= (2t-1)^2-2(2t-1)-1 Please Show Steps.

sasogeek · Answer

ok umm if you have $ (a-b)^2$ it is the same as $ (a^2-2ab+b^2) $  so we simply have to apply this here and then simplify...

  $$ (2t-1)^2-2(2t-1)-1 $$$$=( \ (2t)^2-2(2t)+1\ \ )-(4t-2)-1$$$$ =4t^2-4t+1-4t+2-1$$$$=4t^2-8t+2$$
hence $f(2t-1)=4t^2-8t+2 $

anonymous · Answer

the answer is simple based on (a+b)^2=a^2+b^2+2ab;
so the answer would be (2t-11I^2=4t^2+1-4t
and then 2(2t-1)=4t-2
so over all goes like this 4t^2+1-4t-(4t-2)-1=4t^2+1-4t-4t+2-1=4t^2-8t+2