Question

How many solutions are there for the equation? x2 + 16 = 8x
A. 2
B. 1
C. 0

I chose A..

Answer 1

x^2-8x+16=(x-4)^2=0
x-4=0
x=4

Answer 2

x^(2)-8x+16=0

Factor the trinomial x^(2)-8x+16.
(x-4)(x-4)=0

Set each of the factors of the left-hand side of the equation equal to 0.
x-4=0

Since -4 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 4 to both sides.
x=4

Number of solutions: 1
Answer: B